2023 Boolean w6 using Relational and Logical Operators to Evaluate Logical Boolean Expression Evaluate the logical Boolean expressions in the | Assignment Collections
Computer Science 2023 Boolean w6
2023 Boolean w6 using Relational and Logical Operators to Evaluate Logical Boolean Expression Evaluate the logical Boolean expressions in the | Assignment Collections
Boolean w6
using Relational and Logical Operators to Evaluate Logical (Boolean) Expression
Evaluate the logical (Boolean) expressions in the following exercises and circle the correct answer after you evaluation. For char and String types, use the Unicode collating sequence.
|
Expression |
Result (Circle correct answer) |
|
1. int num1 = 3, num2 = 2; (num1 > num2) |
T F |
|
2. double hours = 12.8; (hours > 40.2) |
T F |
|
3. int funny = 7; (funny ! = 1) |
T F |
|
4. char letter = ‘ A ‘; (‘a’ < letter ) |
T F |
|
5. int count = 1; count < = 4; |
T F |
|
6. double y = -2 . 3; y > = 0.0; |
T F |
|
Expressions Use the following values: X = false, y = false, z = true |
Result (Circle all possible answers) |
|
|
1. ! ( x | | y) | | z |
T F short – circuit |
|
|
2. x && z && y |
T F short – circuit |
|
|
3. ! x | | (y | | ! z) |
T F short – circuit |
|
|
4. x | | (z && (y | | x) ) |
T F short – circuit |
|
|
5. true | | ! z && y |
T F short – circuit |
|
|
6. ! (x | | y) | | x |
T F short – circuit |
|
|
7. z && x && y |
T F short – circuit |
|
|
8. ! x | | (y | | ! z) |
T F short – circuit |
|
|
9. x | | (y && (x | | z) ) |
T F short circuit |
|
|
10. false | | ! x && y |
T F short – circuit |
|
|
|
|
|
|
Expression Use the following values: X = false, y = false, z = true T F (Circle all possible answers)
|
Result (Circle all possible answers) |
|
1. String name1 = “Aaron” ; String name2 = “aaron” ; name1. compareTo(name2)= = 0 |
T F |
|
2. String name1 = “Aaron” ; String name2 = “Aardvark” ; namel. compareTo(name2) > 0 |
T F |
|
3. Boolean flag = true; int a = 2, b = 5, c = 10; (a * b < = c && ! flag) |
T F |
|
4. String name1 = “Aaron” ; String word = “A” ; name1 .compareTo(word) < 0 |
T F |
|
5. int x = 2; double y = 1 . 1; (x – y) = = 0 . 9
|
T F |
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